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Module 03 · Chapters 4

03

Financial Markets I

Money, bonds, and the central bank's interest-rate target.

How the central bank picks i — and why the LM curve became flat.

~30 min· 4 sub-skills·6 exercisesExam frequency · high00% mastered
  1. The goods market told us output adjusts to demand. The next question is: what determines the interest rate that drives investment? In modern central-bank practice, the interest rate is set as a policy choice. But to understand what that choice means, we need the underlying money-market plumbing.

  2. Money demand
    Md  =  $YL(i)M^d \;=\; \$Y \cdot L(i)
    MdM^d
    nominal money demand (cash + checking)
    $Y\$Y
    nominal GDP — transactions volume
    L(i)L(i)
    decreasing in i — the opportunity cost of holding money

    More transactions → more money demanded. Higher interest rate → less, because cash earns nothing while bonds earn i.

  3. Figure · Money-market equilibrium
    MiMᵈi^T
    Modern (rate-targeting): CB picks i, M^s adjusts to clear.

    Vertical M^s, downward-sloping M^d. Equilibrium i where they cross.

  4. Money-market equilibrium condition
    Ms  =  $YL(i)M^s \;=\; \$Y \cdot L(i)

    If M^s rises (CB expansion), i falls. If $Y rises (boom), i rises. This is the LM logic.

  5. Price of a one-period zero
    PB  =  F1+iP_B \;=\; \frac{F}{1 + i}
    PBP_B
    current bond price
    FF
    face value (paid back at maturity)
    ii
    one-period yield

    Solve for i: $i = F/P_B - 1$. Yield and price are inverses around 1.

  6. Exercise · predict shift · +10 XP

    Money demand response to income

    Real income rises 10%. Holding i fixed, what happens to nominal money demand?

    Scenario: ΔY > 0, i unchanged.

  7. Exercise · predict shift · +10 XP

    Money demand response to i

    The interest rate rises. What happens to real money demand?

    Scenario: Δi > 0, $Y unchanged.

  8. Exercise · numerical · +14 XP

    Equilibrium i from M^s and M^d

    $Y = 1000, M^s = 200. The function L(i) = 0.25 − 1.25·i. Find i*.
  9. Exercise · numerical · +14 XP

    Modern LM — what M^s does the CB choose?

    $Y = 1200. The CB targets i = 3% with the L function from above. What M^s must it provide?
  10. Exercise · numerical · +12 XP

    Bond price from yield

    A 1-year zero has face value €100. The 1-year yield is 5%. What is its price today?
  11. Exercise · numerical · +12 XP

    Yield from price

    A 1-year zero with face €100 trades at €92.59. What is its yield?

Mastery check

5 questions · pass with 80%

Answer all five to confirm you've internalised the module. A passing run unlocks the next module.

  1. Q1

    "Bond prices and yields move in the same direction."

  2. Q2

    Which raises real money demand?

  3. Q3

    "In the modern LM model, M^s is endogenous to the interest-rate target."

  4. Q4

    $Y rises and the CB holds M^s fixed. What happens to i?

  5. Q5

    A 1-year zero face €100 trades at €98.04 (i = 2%). The CB raises i to 4%. New price?

0 / 5 answered

Exam pitfalls

  • Treating money demand as a function of *real* income only. It scales with **nominal** $Y, which captures both Y and P.
  • Drawing the LM curve as upward-sloping in the 'modern' framework. The exam in this course uses the flat-LM convention.
  • Confusing M^s changes (which used to set i) with i changes (modern: i is set; M^s adjusts).
  • Saying 'higher rates make bonds more valuable'. They make bonds *more attractive* on a yield basis, but make existing low-coupon bonds *less* valuable.